Crestfallen Studios

Can anyone help me simplifying these Ration algebraic expressions?

Thanks in advance!

Okay. Considering I've done basically nothing on Rational Algerbraic Expressions I'll give it a shot, but don't take my word for it. I'll also have it noted that I was just seeing what I could do with most of these expressions, they are probably wrong. Stupid Maths.

(Note: I use (2) for squared and simply use the divide symbol (/) for divide. No lines or crazy stuff like that. I also put them in quotes to make them easier to see)

1. mx-2nx+my-2ny
/ m(2)-4n(2)

First thing I noticed was you can factorise the bottom:
m(2)-4n(2) = (m+2n)(m-2n) = m(2)-4n(2)+2nm-2nm = m(2)-4n(2)

Then I got stuck. Mainly because the Numerator has xs and ys. Otherwise I'd be set. Oh well, maybe somebody can continue with this line of thought.

2. 2-x
/ x(2)-4

So anyway, I thought it was easier to factorise the bottom:

x(2)-4 = (x+2)(x-2)

2-x
/(x+2)(x-2)

Now I'm not too sure on account of my lack of experiance in this area of maths. Now I'm sure it's due to this lack of experiance that I can't do anything with that. It LOOKS like you can do something with it. I'm not too sure...

3. by-by
/ y-x

Doesn't this just equal 0 as the numerator is 0? by-by=0
0/Anything = 0

Or maybe by-by = (b+b)(y-y) That that trail of thought left me nowhere.

4. x(2)-7x+12
/ 12-7X+x(2)

Is it me, or does this look like the easiest problem in the universe?
Just rearranging the denominator makes:

x(2)-7x+12
/x(2)-7x+12

Which basically means 1/1. Right?

5. 3x(2)+4x-4
/ 4-9x

Okay. No matter how hard I try, I ccouldn't factorise the top in the form (3x+ )(x- ) but then something hit me.

(1.5x-1)(2x+4) = 3x(2)+6x-2x-4 = 3x(2)+4x-4!
Right, so I've factorised the top. Now for the bottom, simple.

(2+3x)(2-3x) = 4-6x+6x-9x(2) = 4-9x(2)
Brilliant! I've factorised both Numerator and Denominator.

(1.5x-1)(2x+4)
/(2+3x)(2-3x)

So wonderful... where's the fuggin' common factor! This sucks.

Okay, you can't factorise any of these properly (easily, you probably can with some overly complicated method), they suck. I wanna see if anybody knows how to solve them. I'm interested in the technique and answer now. And one of you better know!

thanks for helping out

Don't thank me yet. It might all be completely wrong.

[x(m-2n) + y(m-2n)]/[(m-2n)(m+2n)]
(x+y)(m-2n)/(m-2n)(m+2n)
(x+y)/(m+2n)

(2-x)/(x+2)(x-2)
(-1)(x-2)/(x+2)(x-2)
-1/(x+2)

0

1

(x+2)(3x-2)/(2-3x)(2+3x)
(x+2)(3x-2)/(-1)(3x-2)(2+3x)
-(x+2)/(3x+2)

Ahh! I see what you did.

Dammit NS, I just had it....

i see how you do it now. thanks

Didn't I outlaw math on mIRC and the boards a while ago?

oh, i din't know that

Hahaha, he takes strayed seriously.

Teenr0cker wrote:Hahaha, he takes strayed seriously.

And why shouldn't he?

if that was official that is

Dammit, why haven't I destroyed algebra yet?

Oh yes, I don't have enough power in my genesis device.

math, algebra, geometry, trigonometry are helpful especially if you plan on taking a software (especially games) programming career..